3.30 \(\int \frac{1}{\csc ^{\frac{4}{3}}(a+b x)} \, dx\)

Optimal. Leaf size=53 \[ \frac{3 \cos (a+b x) \text{Hypergeometric2F1}\left (\frac{1}{2},\frac{7}{6},\frac{13}{6},\sin ^2(a+b x)\right )}{7 b \sqrt{\cos ^2(a+b x)} \csc ^{\frac{7}{3}}(a+b x)} \]

[Out]

(3*Cos[a + b*x]*Hypergeometric2F1[1/2, 7/6, 13/6, Sin[a + b*x]^2])/(7*b*Sqrt[Cos[a + b*x]^2]*Csc[a + b*x]^(7/3
))

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Rubi [A]  time = 0.0213212, antiderivative size = 53, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 10, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3772, 2643} \[ \frac{3 \cos (a+b x) \, _2F_1\left (\frac{1}{2},\frac{7}{6};\frac{13}{6};\sin ^2(a+b x)\right )}{7 b \sqrt{\cos ^2(a+b x)} \csc ^{\frac{7}{3}}(a+b x)} \]

Antiderivative was successfully verified.

[In]

Int[Csc[a + b*x]^(-4/3),x]

[Out]

(3*Cos[a + b*x]*Hypergeometric2F1[1/2, 7/6, 13/6, Sin[a + b*x]^2])/(7*b*Sqrt[Cos[a + b*x]^2]*Csc[a + b*x]^(7/3
))

Rule 3772

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x])^(n - 1)*((Sin[c + d*x]/b)^(n - 1)
*Int[1/(Sin[c + d*x]/b)^n, x]), x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin{align*} \int \frac{1}{\csc ^{\frac{4}{3}}(a+b x)} \, dx &=\csc ^{\frac{2}{3}}(a+b x) \sin ^{\frac{2}{3}}(a+b x) \int \sin ^{\frac{4}{3}}(a+b x) \, dx\\ &=\frac{3 \cos (a+b x) \, _2F_1\left (\frac{1}{2},\frac{7}{6};\frac{13}{6};\sin ^2(a+b x)\right )}{7 b \sqrt{\cos ^2(a+b x)} \csc ^{\frac{7}{3}}(a+b x)}\\ \end{align*}

Mathematica [A]  time = 0.142166, size = 68, normalized size = 1.28 \[ -\frac{\cos (a+b x) \left (\text{Hypergeometric2F1}\left (\frac{1}{2},\frac{5}{6},\frac{3}{2},\cos ^2(a+b x)\right )+3 \sqrt [6]{\sin ^2(a+b x)}\right )}{4 b \sqrt [6]{\sin ^2(a+b x)} \sqrt [3]{\csc (a+b x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Csc[a + b*x]^(-4/3),x]

[Out]

-(Cos[a + b*x]*(Hypergeometric2F1[1/2, 5/6, 3/2, Cos[a + b*x]^2] + 3*(Sin[a + b*x]^2)^(1/6)))/(4*b*Csc[a + b*x
]^(1/3)*(Sin[a + b*x]^2)^(1/6))

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Maple [F]  time = 0.09, size = 0, normalized size = 0. \begin{align*} \int \left ( \csc \left ( bx+a \right ) \right ) ^{-{\frac{4}{3}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/csc(b*x+a)^(4/3),x)

[Out]

int(1/csc(b*x+a)^(4/3),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\csc \left (b x + a\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="maxima")

[Out]

integrate(csc(b*x + a)^(-4/3), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{1}{\csc \left (b x + a\right )^{\frac{4}{3}}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="fricas")

[Out]

integral(csc(b*x + a)^(-4/3), x)

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\csc ^{\frac{4}{3}}{\left (a + b x \right )}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)**(4/3),x)

[Out]

Integral(csc(a + b*x)**(-4/3), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\csc \left (b x + a\right )^{\frac{4}{3}}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/csc(b*x+a)^(4/3),x, algorithm="giac")

[Out]

integrate(csc(b*x + a)^(-4/3), x)